Deflection and Slope in Simply Supported Beams | Beam Deflection Table, Formula

Updated: Jan 21, 2021

A simply supported beam rests on two supports(one end pinned and one end on roller support) and is free to move horizontally. The deflection and slope of any beam(not particularly a simply supported one) primary depend on the load case it is subjected upon. If the load case varies, its deflection, slope, shear force and bending moment get changed.

This article will help you find the deflection and slope developed at any point of a simply supported beam, subjected to any load.

What is a Simply Supported Beam?

The simply supported beam is one of the most modest structures. The configuration of a simply supported beam is so simple having one hinge support at an end and roller support at the other end. With this setup the beam can only rotate horizontally, any vertical moment is restained.

Simply supported beam, Deck slab, Simply supported beam in bridge
Simply supported deck slab

This roller support also helps the beam expand or contract axially, although the free horizontal movement is prevented by the other support.

This is a determinant structure, which means that if an internal hinge is inserted or any of these supports(pin or roller) is removed, the beam can not carry the load anymore. In this case, the beam will freely move under loading.

Deflected shape of simply supported beam, beam deflection under loaidng
Deflection in simply supported beam

Finding Deflection and Slope

There are multiple methods like double integration method, Macaulay's method, Conjugate beam method, Castigliano's theorem, Principle of superposition which help us find the deflection and slope of a beam.

Here we will use the double integration method, which is a simple, effective and straight forward method, that can be used to solve any type of question.

From the Euler-Bernoulli bending theory, at a point along a beam, we have:

1/R = M/EI

Where: R is the radius of curvature of the point

M is the bending moment at that point

EI is the flexural rigidity of the member, E is Young's modulus of the beam material, I is the second moment of area.

We also have dx = R dθ and so 1/R = dθ/dx. Again for small displacements, θ ≃ tan θ ≃ dy/dx and so:

1 / R = d²y / dx² = M / EI

The formula used to find slope and deflection of the beam

The bending moment at any point of the beam section can be found using the double integration formula, that is given below.

  • M is the Bending Moment at a particular section, which is a function of x

  • EI is the flexural rigidity of the member

  • y represents the vertical deflection of the beam and x is the lateral direction.

  • dy/dx represents the slope of the beam at that particular point.

Using this relation, upon integrating, the function for dy/dx(slope) can be found. Then, putting the appropriate value of x we can find the slope.

Upon integrating again and putting the value of x, the deflection(y) can be determined.

Seems confusing? Let’s work out an example, you can be an expert then.


Find the maximum deflection and slope at both the ends of the beam as shown.

Eccentrically loaded beam, Simply supported beam and non uniform loading
Eccentric load case

Our initial step would be drawing a rough deflection diagram.

Deflected shape of beam, Deflection of beam
Deflected shape of beam

Here in the deflection diagram θA and θB are the slope at point A and B respectively due to the load P. The midpoint deflection is δc and the maximum deflection due to point load P is δmax.

Step 1: Finding the reactions at support(s)

We can use the horizontal equilibrium (ΣH = 0), vertical equilibrium (ΣV = 0) and moment equation (ΣMx = 0) for the reaction calculation.

The reaction at A is Pb/L and B is Pa/L.

Step 2: Writing bending moment pattern at different sections of the beam

In this case, the bending moment from L = 0 to L = a follows one pattern and the bending moment from L = a to L = a + b follows another pattern.